An arrow is fired straight upwards at a speed of 50.0m/s from the top of a building 100m above the ground. How long does it take to strike the...

Hello!

Using Newton's Second Law, one can obtain the known formulas for such a movement:

 

where is the time from the start, is the initial speed, is the initial height and is the gravity acceleration. is the speed of an arrow as a function of time, is its height.

The time until an arrow strikes the ground must be positive and satisfy...

Hello!

Using Newton's Second Law, one can obtain the known formulas for such a movement:

 

where is the time from the start, is the initial speed, is the initial height and is the gravity acceleration. is the speed of an arrow as a function of time, is its height.

The time until an arrow strikes the ground must be positive and satisfy the equation  (ground level is assumed zero). This is a quadratic equation. In numbers it is:

or

So I used the quadratic formula here. The solution before the root is negative.

Next, the maximum height is when an arrow finishes its rise and will begin to fall, i.e. when This is   The height above the ground is

And the final speed is the speed at     This means    downwards.

So the answers are: an arrow strikes the ground after about 11.7 s, its speed before that moment will be about 67 m/s downwards, and the maximum height above the ground will be about 225 m.