Write an expression for the apparent nth term of the sequence. (assume that n begins with 1)

Every term has a '1' in its expression. So the nth term will also have '1' as the beginning value.

When we consider the part after '1+'......

etc....

We can see numerator is 1 less than denominator.

When we consider denominator;

etc....

So the denominator of the...

Every term has a '1' in its expression. So the nth term will also have '1' as the beginning value.

When we consider the part after '1+'......

etc....

We can see numerator is 1 less than denominator.

When we consider denominator;

etc....

So the denominator of the nth term will be .

Then the numerator will be

Finally the nth term will look like;