A 1-hectare field contains 2500 bean plants having a total surface area of 557 Ambient temperatures is 21 °C, winds are calm, and humidity...

Hello!

You didn't specify what "step 2 of the Analysis" is and the average loss calculated. I suppose that this loss has some numeric value. We will denote it as

Note that this loss should include time in its units, since it is the loss of water from the unit of an area over a unit of time. So the average loss is  

Then the answer is simple. If each plant is...

Hello!

You didn't specify what "step 2 of the Analysis" is and the average loss calculated. I suppose that this loss has some numeric value. We will denote it as

Note that this loss should include time in its units, since it is the loss of water from the unit of an area over a unit of time. So the average loss is  

Then the answer is simple. If each plant is transpiring at the average loss of then all plants are transpiring each hour:

I * (1 hour) * (the total surface area of plants) = I*557 (mL).

Probably, the result will be relatively large. We may divide it by 1000 to obtain the result in liters (L).  If the number found for corresponds to the loss per day, then we should divide this formula by 24 (hours in a day).