This question is what we called composite functions in Mathematics. A composite function is defined as applying one function to the results of another. If we say the result of f() is sent through g(), we can express mathematically as follows:
`(g@ f)(x)`
Which translates as the following:
`g(f(x))`
And vice versa, like in our example, we say the result of g() is send through f():
`(f @ g)(x)`
which translates as:
`f (g(x))`
PLEASE...
This question is what we called composite functions in Mathematics. A composite function is defined as applying one function to the results of another. If we say the result of f() is sent through g(), we can express mathematically as follows:
`(g@ f)(x)`
Which translates as the following:
`g(f(x))`
And vice versa, like in our example, we say the result of g() is send through f():
`(f @ g)(x)`
which translates as:
`f (g(x))`
PLEASE NOTE: `(g @ f(x))` is NOT equal to `(g @ f) `
Now let's answer our question:
`f(x) = 7/(x+5)`
`g(x) =1/x`
Now write what we solving for as shown above:
`(f@g) (x) = f(g(x))`
Now where ever you see x substitute g(x):
`f(g(x)) = 7/ (g(x) +5)`
We know the value of g(x), now we substitute it
`f(g(x)) = 7/((1/x) + 5)`
We can simplify this to get rid of the fraction in the denominator. Multiply 5 by x/x to get a common denominator and then add them together.
`f(g(x)) = 7/((1/(x)) + ((5x)/x))`
`f(g(x)) = 7/((1 + 5x)/x)`
We can simplify this more by multiplying the numerator and the denominator by x. This will get rid of the fraction in the denominator.
`f(g(x)) = 7/((5x + 1)/x) * x/x = (7x)/(5x + 1)`
SUMMARY:
- Convert `(f@g) ` into `f (g(x))`
- ANSWER:
`(f@g) = (7x)/(5x + 1)`
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