`1/3, 2/9, 4/27, 8/81` Write an expression for the apparent nth term of the sequence. (assume that n begins with 1)

Numerator contains powers of 2 starting with `2^0=1` while the denominator contains powers of 3 starting with `3^1=3.` Therefore, the `n`th term is

`a_n=2^(n-1)/3^n`                       

Numerator contains powers of 2 starting with `2^0=1` while the denominator contains powers of 3 starting with `3^1=3.` Therefore, the `n`th term is

`a_n=2^(n-1)/3^n`