We are given the volumetric flow rate to be:
`(12L)/(4 minutes) = 3 L/min`
Also since our final answer has to be in centimeters, we have to convert the volumetric flowrate obtained above into square centimeters:
`3L = 3000cm^3`
Therefore the volumetric flowrate is:
`3000 (cm^3)/min`
In order to determine the speed of the water, we have to first know that the volume of the cylinder is:
`V = pi * r^2 * h`
`pi...
We are given the volumetric flow rate to be:
`(12L)/(4 minutes) = 3 L/min`
Also since our final answer has to be in centimeters, we have to convert the volumetric flowrate obtained above into square centimeters:
`3L = 3000cm^3`
Therefore the volumetric flowrate is:
`3000 (cm^3)/min`
In order to determine the speed of the water, we have to first know that the volume of the cylinder is:
`V = pi * r^2 * h`
`pi = 3.14`
`r = 0.74cm` ( r = raduis)
`V = 3000 (cm^3 )/min` Note in this equation V is volumetric flowrate, not volume.
Now we need to determine, h - the height:
`h = (3000/ (pi *(0.74)^2 ))`
`h = 1744.69 (cm)/min`
We can round off the above answer to as the following:
`h = 1745 (cm)/min`
The speed of the water going through the pipe is 1745 cm/min
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