Wednesday, June 3, 2015

Write an expression for the apparent nth term of the sequence. (assume that n begins with 1)

 Let us first write the first two terms as fractions as well.



In the numerator we have powers of 3 ( and ). In the denominator we have factorials (). Therefore, the th term of the sequence is 



We have to put  because both powers and factorials start with 0 ()

 Let us first write the first two terms as fractions as well.



In the numerator we have powers of 3 ( and ). In the denominator we have factorials (). Therefore, the th term of the sequence is 



We have to put  because both powers and factorials start with 0 ()

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